a^2+1.5^2=64

Solution for a^2+1.5^2=64 equation:

a^2+1.5^2=64

We move all terms to the left:

a^2+1.5^2-(64)=0

determiningTheFunctionDomain
a^2-64+1.5^2=0

We add all the numbers together, and all the variables

a^2-61.75=0

a = 1; b = 0; c = -61.75;
Δ = b2-4ac
Δ = 02-4·1·(-61.75)
Δ = 247
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{247}}{2*1}=\frac{0-\sqrt{247}}{2}
=-\frac{\sqrt{}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{247}}{2*1}=\frac{0+\sqrt{247}}{2}
=\frac{\sqrt{}}{2}
$